2(x^2+5x-528)=0

Solution for 2(x^2+5x-528)=0 equation:

2(x^2+5x-528)=0

We multiply parentheses

2x^2+10x-1056=0

a = 2; b = 10; c = -1056;
Δ = b2-4ac
Δ = 102-4·2·(-1056)
Δ = 8548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8548}=\sqrt{4*2137}=\sqrt{4}*\sqrt{2137}=2\sqrt{2137}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{2137}}{2*2}=\frac{-10-2\sqrt{2137}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{2137}}{2*2}=\frac{-10+2\sqrt{2137}}{4}
$